Gujarati
Hindi
2. Electric Potential and Capacitance
medium

An infinite nonconducting sheet of charge has a surface charge density of $10^{-7}\  C/m^2$. The separation between two equipotential surfaces near the sheet whose potential differ by $ 5\,V$  is

A

$0.88$ $ cm$

B

$0.88 $ $mm$

C

$0.88 $ $m$

D

$5$ $ \times $ $10^{-7}$ $ m$

Solution

$V=E d=\frac{\sigma}{2 \varepsilon_{0}} d$

$\therefore D=\frac{(2 \varepsilon)_{0 V}}{\sigma}$

$=2 \frac{\left(8.86 \times 10^{-12}\right)(5)}{10^{-7}}$

$=0.88 \times 10^{-3} \mathrm{m}$

$=0.88 \mathrm{mm}$

Standard 12
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.