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2. Electric Potential and Capacitance
medium
An infinite nonconducting sheet of charge has a surface charge density of $10^{-7}\ C/m^2$. The separation between two equipotential surfaces near the sheet whose potential differ by $ 5\,V$ is
A
$0.88$ $ cm$
B
$0.88 $ $mm$
C
$0.88 $ $m$
D
$5$ $ \times $ $10^{-7}$ $ m$
Solution
$V=E d=\frac{\sigma}{2 \varepsilon_{0}} d$
$\therefore D=\frac{(2 \varepsilon)_{0 V}}{\sigma}$
$=2 \frac{\left(8.86 \times 10^{-12}\right)(5)}{10^{-7}}$
$=0.88 \times 10^{-3} \mathrm{m}$
$=0.88 \mathrm{mm}$
Standard 12
Physics