2. Electric Potential and Capacitance
hard

Two charged conducting spheres of radii $a$ and $b$ are connected to each other by a conducting wire. The ratio of charges of the two spheres respectively is:

A

$\sqrt{\mathrm{ab}}$

B

$a b$

C

$\frac{a}{b}$

D

$\frac{\mathrm{b}}{\mathrm{a}}$

(JEE MAIN-2024)

Solution

Potential at surface will be same

$\frac{\mathrm{Kq}_1}{\mathrm{a}}=\frac{\mathrm{Kq}}{\mathrm{b}}$

$\frac{\mathrm{q}_1}{\mathrm{q}_2}=\frac{\mathrm{a}}{\mathrm{b}}$

Standard 12
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.