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2. Electric Potential and Capacitance
hard
Two charged conducting spheres of radii $a$ and $b$ are connected to each other by a conducting wire. The ratio of charges of the two spheres respectively is:
A
$\sqrt{\mathrm{ab}}$
B
$a b$
C
$\frac{a}{b}$
D
$\frac{\mathrm{b}}{\mathrm{a}}$
(JEE MAIN-2024)
Solution
Potential at surface will be same
$\frac{\mathrm{Kq}_1}{\mathrm{a}}=\frac{\mathrm{Kq}}{\mathrm{b}}$
$\frac{\mathrm{q}_1}{\mathrm{q}_2}=\frac{\mathrm{a}}{\mathrm{b}}$
Standard 12
Physics
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