An oil drop of $12$ excess electrons is held stationary under a constant electric field of $2.55 \times 10^{4}\; N\,C ^{-1}$ (Millikan's oil drop experiment). The density of the oil is $1.26 \;g \,cm ^{-3} .$ Estimate the radius of the drop. $\left(g=9.81\; m s ^{-2} ; e=1.60 \times 10^{-19}\; \,C \right)$
$7.24 \times 10^{-4} \;cm$.
$9.82 \times 10^{-4} \;mm$.
$8.34 \times 10^{-4} \;m$.
$4.25 \times 10^{-5} \;mm$.
Charge $Q$ is distributed non-uniformly over a ring of radius $R, P$ is a point on the axis of ring at a distance $3R$ from its centre. Which of the following is a wrong statement.
Electric field at centre $O$ of semicircle of radius $a$ having linear charge density $\lambda$ given is given by
Three charged particle $A, B$ and $C$ with charges $-4 q, 2 q$ and $-2 q$ are present on the circumference of a circle of radius $d$. the charged particles $A, C$ and centre $O$ of the circle formed an equilateral triangle as shown in figure. Electric field at $O$ along $x-$direction is
Electric field strength due to a point charge of $5\,\mu C$ at a distance of $80\, cm$ from the charge is
Two point charges of $20\,\mu \,C$ and $80\,\mu \,C$ are $10\,cm$ apart. Where will the electric field strength be zero on the line joining the charges from $20\,\mu \,C$ charge......$m$