An urn contains 5 red marbles, 4 black marbles and 3 white marbles. Then number of ways in which 4 m

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6.Permutation and Combination

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An urn contains $5$ red marbles, $4$ black marbles and $3$ white marbles. Then the number of ways in which $4$ marbles can be drawn so that at the most three of them are red is

$540$

$450$

$420$

$490$

(JEE MAIN-2020)

Solution

The question does not mention that whether same coloured marbles are distinct or identical. So, assuming they are distinct our required answer $=^{12} \mathrm{C}_{4}-^{5} \mathrm{C}_{4}=490$

Standard 11

Mathematics

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An urn contains $5$ red marbles, $4$ black marbles and $3$ white marbles. Then the number of ways in which $4$ marbles can be drawn so that at the most three of them are red is

Solution

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