Are the following pair of sets equal ? Give reasons.
$A = \{ 2,3\} ,\quad \,\,\,B = \{ x:x$ is solution of ${x^2} + 5x + 6 = 0\} $
$A = \{ 2,3\} ,\quad \,\,\,B = \{ x:x$ is solution of ${x^2} + 5x + 6 = 0\} $
The equation $x^{2}+5 x+6=0$ can be solved as:
$x(x+3)+2(x+3)=0$
$(x+2)(x+3)=0$
$x=-2$ or $x=-3$
$\therefore A=\{2,3\} ; B=\{-2,-3\}$
$\therefore A \neq B$
List all the elements of the following sers :
$F = \{ x:x$ is a consonant in the Englishalphabet which precedes $k\} $
If $Q = \left\{ {x:x = {1 \over y},\,{\rm{where \,\,}}y \in N} \right\}$, then
Make correct statements by filling in the symbols $\subset$ or $ \not\subset $ in the blank spaces:
$\{ x:x$ is a triangle in a plane $\} \ldots \{ x:x$ is a rectangle in the plane $\} $
Write the following sets in roster form :
$C = \{ x:x{\rm{ }}$ is a two-digit natural number such that sum of its digits is $8\} $
Write the following as intervals :
$\{ x:x \in R, - 4\, < \,x\, \le \,6\} $