Area of quadrilaterals formed by drawing tangents at ends of latus recta of frac{{{x^2}}}{4} +

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10-2. Parabola, Ellipse, Hyperbola

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Area of the quadrilaterals formed by drawing tangents at the ends of latus recta of $\frac{{{x^2}}}{4} + \frac{{{y^2}}}{1} = 1$ is

A

$\frac{{16}}{{\sqrt 3 }}$

B

$\frac{{8}}{{\sqrt 3 }}$

C

$\frac{{4}}{{\sqrt 3 }}$

D

$4\sqrt 3 $

Solution

$\Delta=\frac{2 \mathrm{a}^{2}}{\mathrm{e}} \quad \mathrm{e}=\frac{\sqrt{3}}{2}$

$\mathrm{a}=2 \quad \Rightarrow \mathrm{D}=\frac{16}{\sqrt{3}}$

Standard 11

Mathematics

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