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10-2. Parabola, Ellipse, Hyperbola
normal
Area of the quadrilaterals formed by drawing tangents at the ends of latus recta of $\frac{{{x^2}}}{4} + \frac{{{y^2}}}{1} = 1$ is
A
$\frac{{16}}{{\sqrt 3 }}$
B
$\frac{{8}}{{\sqrt 3 }}$
C
$\frac{{4}}{{\sqrt 3 }}$
D
$4\sqrt 3 $
Solution
$\Delta=\frac{2 \mathrm{a}^{2}}{\mathrm{e}} \quad \mathrm{e}=\frac{\sqrt{3}}{2}$
$\mathrm{a}=2 \quad \Rightarrow \mathrm{D}=\frac{16}{\sqrt{3}}$
Standard 11
Mathematics
