Area of the rhombus bounded by the four lines, $ax \pm by \pm c = 0$ is :
$\frac{{{c^2}}}{{2\,ab}}$
$\frac{{2\,{c^2}}}{{ab}}$
$\frac{{4\,{c^2}}}{{ab}}$
$\frac{{ab}}{{4\,{c^2}}}$
The pair of straight lines $x^2 - 4xy + y^2 = 0$ together with the line $x + y + 4 = 0$ form a triangle which is :
If the straight lines $x + 3y = 4,\,\,3x + y = 4$ and $x +y = 0$ form a triangle, then the triangle is
$ABC$ is an isosceles triangle . If the co-ordinates of the base are $(1, 3)$ and $(- 2, 7) $, then co-ordinates of vertex $A$ can be :