The equation of perpendicular bisectors of the sides $AB$ and $AC$ of a triangle $ABC$ are $x - y + 5 = 0$ and $x + 2y = 0$ respectively. If the point $A$ is $(1,\; - \;2)$, then the equation of line $BC$ is

  • [IIT 1986]
  • A

    $23x + 14y - 40 = 0$

  • B

    $14x - 23y + 40 = 0$

  • C

    $23x - 14y + 40 = 0$

  • D

    $14x + 23y - 40 = 0$

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