A 5, μ F capacitor is charged fully by a 220,V supply. It is then disconnected from supply and is c

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2. Electric Potential and Capacitance

medium

A $5\, \mu F$ capacitor is charged fully by a $220\,V$ supply. It is then disconnected from the supply and is connected in series to another uncharged $2.5\;\mu F$ capacitor. If the energy change during the charge redistribution is $\frac{ X }{100} \;J$ then value of $X$ to the nearest integer is$.....$

$4$

$10$

$9$

$15$

(JEE MAIN-2020)

$u _{ i }=\frac{1}{2} \times 5 \times 10^{-6}(220)^{2}$

Final common potential

$v=\frac{220 \times 5+0 \times 2.5}{5+2.5}=220 \times \frac{2}{3}$

$u _{ f }=\frac{1}{2}(5+2.5) \times 10^{-6}\left(220 \times \frac{2}{3}\right)^{2}$

$\Delta u = u _{ f }- u _{ i }$

$\Delta u =-403.33 \times 10^{-4}$

$\Rightarrow-403.33 \times 10^{-4}=\frac{ X }{100}$

$X=-4.03$

or magnitude or value of $X$ is approximate $4$

Standard 12

Physics

easy

(AIEEE-2003)

medium

(AIIMS-2004)

easy

(AIPMT-1996)

medium

medium