As shown in the figure, the uniform magnetic field between the two identical plates is $B$. There is a hole in plate. If through this hole a particle of charge $q$, mass $m$ and energy $E$ enters this magnetic field, then the particle will not collide with the upper plate provided
$B > \frac{{2mE}}{{qd}}$
$B > \frac{{\sqrt {2mE} }}{{qd}}$
$B < \frac{{2mE}}{{qd}}$
$B < \frac{{\sqrt {2mE} }}{{qd}}$
This question has Statement $1$ and Statement $2$ . Of the four choices given after the Statements, choose the one that best describes the two Statements.
Statement $1$: A charged particle is moving at right angle to a static magnetic field . During the motion the kinetic energy of the charge remains unchanged.
Statement $2$: Static magnetic field exert force on a moving charge in the direction perpendicular to the magnetic field.
A proton is moving along $Z$-axis in a magnetic field. The magnetic field is along $X$-axis. The proton will experience a force along
A proton and an electron both moving with the same velocity $v$ enter into a region of magnetic field directed perpendicular to the velocity of the particles. They will now move in circular orbits such that
Assertion : A proton and an alpha particle having the same kinetic energy are moving in circular paths in a uniform magnetic field. The radii of their circular paths will be equal.
Reason : Any two charged particles having equal kinetic energies and entering a region of uniform magnetic field $\overrightarrow B $ in a direction perpendicular to $\overrightarrow B $, will describe circular trajectories of equal radii.
An electron is moving along the positive $X$$-$axis. You want to apply a magnetic field for a short time so that the electron may reverse its direction and move parallel to the negative $X$$-$axis. This can be done by applying the magnetic field along