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Assertion : A proton and an alpha particle having the same kinetic energy are moving in circular paths in a uniform magnetic field. The radii of their circular paths will be equal.
Reason : Any two charged particles having equal kinetic energies and entering a region of uniform magnetic field $\overrightarrow B $ in a direction perpendicular to $\overrightarrow B $, will describe circular trajectories of equal radii.
If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
If Assertion is correct but Reason is incorrect.
If both the Assertion and Reason are incorrect.
Solution
The radius of the circular path is given by
$r=\frac{m v}{q B}=\frac{\sqrt{2 m K}}{q B} ;$ where $K=\frac{1}{2} m v^{2}$
since $K$ and $B$ are the same for the two particles, $r \propto \frac{\sqrt{m}}{q} .$ Now, the charge of an alpha particle is twice that of a proton and its mass is four times the mass of a proton, $\sqrt{m} / q$ will be the same for both particles. Hence, $r$ will be the same for both particles.