6-2.Equilibrium-II (Ionic Equilibrium)
medium

At $298$ $K$ temp., the solubility product for $AgCl$ is $1.5 \times {10^{ - 10}}$. Calculate its solubility in gram/ Litre in pure water.

Option A
Option B
Option C
Option D

Solution

$1.75 \times 10^{-3} \mathrm{~g} \mathrm{~L}^{-1}$

Standard 11
Chemistry

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