If S and {K_{sp}} are respectively solubility and solubility product of a sparingly soluble binary e

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6-2.Equilibrium-II (Ionic Equilibrium)

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If $S$ and ${K_{sp}}$ are respectively solubility and solubility product of a sparingly soluble binary electrolyte, then

A

$S = {K_{sp}}$

B

$S = K_{sp}^2$

C

$S = \sqrt {{K_{sp}}} $

D

$S = \frac{1}{2}{K_{sp}}$

Solution

(c) For a binary electrolyte, so that

${K_{sp}} = S \times S = {S^2}$

$S = \sqrt {{K_{sp}}} $.

Standard 11

Chemistry

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