At any instant the ratio of the amount of rad | vedclass

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Question

(a) Number of half lives in two days four substance $1$ and $2$ respectively are $n_1 =\frac{{2 	imes 24}}{{12}} = 4$ and ${n_2} = \frac{{2 	imes 24

Vedclass · Accepted Answer

$ 1 : 1$

Vedclass · Answer

(a) Number of half lives in two days four substance $1$ and $2$ respectively are $n_1 =\frac{{2 	imes 24}}{{12}} = 4$ and ${n_2} = \frac{{2 	imes 24}}{{1.6}} = 3$ 

By using $N = {N_0}{\left( {\frac{1}{2}} ight)^n}$

==> $\frac{{{N_1}}}{{{N_2}}} = \frac{{{{({N_0})}_1}}}{{{{({N_0})}_2}}} 	imes \frac{{{{\left( {\frac{1}{2}} ight)}^{{n_1}}}}}{{{{\left( {\frac{1}{2}} ight)}^{{n_2}}}}}$

$ = \frac{2}{1} 	imes \frac{{{{\left( {\frac{1}{2}} ight)}^4}}}{{{{\left( {\frac{1}{2}} ight)}^3}}} = \frac{1}{1}$

At any instant the ratio of the amount of radioactive substances is $2 : 1$. If their half lives be respectively $12$ and $16$ hours, then after two days, what will be the ratio of the substances

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