Carbon - 14 decays with half-life of about 5,800, years . In a sample of bone, ratio of carbon - 14

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13.Nuclei

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Carbon $ - 14$ decays with half-life of about $5,800\, years$. In a sample of bone, the ratio of carbon $ - 14$ to carbon $ - 12$ is found to be $\frac{1}{4}$ of what it is in free air. This bone may belong to a period about $x$ centuries ago, where $x$ is nearest to

A

$2 \times 58$

B

$58$

C

$58/2$

D

$3 \times 58$

Solution

(a) To becomes $\frac{1}{4}\, th$, it requires time of two half lives

$i.e.,t = 2({T_{1/2}}) = 2 \times 5800 = 2 \times 58$centuries

Standard 12

Physics

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