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3-1.Vectors
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At what angle should the two forces $2 P$ and $\sqrt{2} P$ act so that the resultant force is $P \sqrt{10}$ ?
A$45^{\circ}$
B$60^{\circ}$
C$90^{\circ}$
D$120^{\circ}$
Solution
(a)
$P \sqrt{10}=\sqrt{4 P^2+2 P^2+4 \sqrt{2} P^2 \cos \theta}$
$\therefore \theta=45^{\circ}$
$P \sqrt{10}=\sqrt{4 P^2+2 P^2+4 \sqrt{2} P^2 \cos \theta}$
$\therefore \theta=45^{\circ}$
Standard 11
Physics