Block A of mass 4 kg is to be kept at rest against a smooth vertical wall by applying a force F as s

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4-1.Newton's Laws of Motion

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Block $A$ of mass $4 \;kg$ is to be kept at rest against a smooth vertical wall by applying a force $F$ as shown in figure. The force required is .......... $N$ $\left(g=10 m / s ^2\right)$

A

$40 \sqrt{2}$

B

$20 \sqrt{2}$

C

$10 \sqrt{2}$

D

$15 \sqrt{2}$

Solution

(a)

so in vertical; for equilibrium

$F \sin 45^{\circ} =m g=40$

$\Rightarrow f=\frac{40}{\sin 45^{\circ}}=40 \sqrt{2}\,N$

Standard 11

Physics

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