4-1.Newton's Laws of Motion
medium

A body of weight $2\, kg$ is suspended as shown in the figure. The tension ${T_1}$ in the horizontal string (in kg wt) is

A

$2/\sqrt 3 $

B

$\sqrt 3 /2$

C

$2\sqrt 3 $

D

$2$

Solution

(c)$T\sin 30 = 2kg\,wt$

$⇒$ $T = 4\,kg\,wt$ 

${T_1} = T\cos 30^o$

$ = 4\cos 30^o$

$ = 2\sqrt 3 $

Standard 11
Physics

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