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4-1.Newton's Laws of Motion
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Block $B$ moves to the right with a constant velocity $v_0$. The velocity of body $A$ relative to $B$ is:
A
$\frac{v_0}{2}$, towards right
B
.$\frac{v_0}{2}$, towards left
C
.$\frac{3v_0}{2}$, towards left
D
.$\frac{3v_0}{2}$, towards right
Solution

From constrained
$V_0-V_A-V_A +V_0+V_0=0$
$V_A =\frac{3 V_0}{2}$
$V_{A B}=V_A-V_B =\frac{3 V_0}{2}-V_0$
$= \frac{V_0}{2} \text { (towards Right) }$
Standard 11
Physics
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