Gujarati
Hindi
4-1.Newton's Laws of Motion
normal

Block $B$ moves to the right with a constant velocity $v_0$. The velocity of body $A$ relative to $B$ is:

A

$\frac{v_0}{2}$, towards right

B

.$\frac{v_0}{2}$, towards left

C

.$\frac{3v_0}{2}$, towards left

D

.$\frac{3v_0}{2}$, towards right

Solution

From constrained

$V_0-V_A-V_A +V_0+V_0=0$

$V_A =\frac{3 V_0}{2}$

$V_{A B}=V_A-V_B =\frac{3 V_0}{2}-V_0$

$= \frac{V_0}{2} \text { (towards Right) }$

Standard 11
Physics

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