4.Chemical Bonding and Molecular Structure
medium

Bond order of $1.5$ is shown by-

A

$O_{2}^+$

B

$O_{2}^-$

C

$O_2^{2-}$

D

$O_2$

(AIPMT-2012)

Solution

Bond order $=\frac{\text { bonding M.O. } {-} \text {antibonding M.O. }}{2}$

Bond order of $\mathrm{O}_{2}^{+}=\frac{10-5}{2}=2.5$

Bond order of $\mathrm{O}_{2}^{-}=\frac{10-7}{2}=1.5$

Bond order of $\mathrm{O}_{2}^{2-}=\frac{10-8}{2}=1.0$

Bond order of $\mathrm{O}_{2}=\frac{10-6}{2}=2$

Standard 11
Chemistry

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