The correct stability order for $N_2$ and its given ions is :-
$N_2 > N_2^+ > N_2^- > N_2^{-2}$
$N_2^- > N_2^+ > N_2 > N_2^{-2}$
$N_2^+ > N_2^- > N_2 > N_2^{-2}$
$N_2 > N_2^+ = N_2^- > N_2^{-2}$
The paramagnetic nature of oxygen can be explained by
Calculate the bond order of ${{\rm{N}}_2},{{\rm{O}}_2}{\rm{,O}}_2^ + $ and ${\rm{O}}_2^ - $
According to $MOT$ which of following is correct
What is the number of unpaired electron(s) in the highest occupied molecular orbital of the following species : $N _2: N _2^{+} ; O _2 ; O _2^{+}$?
Four diatomic species are listed below. Identify the correct order in which the bond order is increasing in them :