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11.Thermodynamics
hard
Carnot cycle (reversible) of a gas represented by a Pressure-Volume curve is shown in the diagramConsider the following statements
$I.$ Area $ABCD =$ Work done on the gas
$II.$ Area $ABCD =$ Net heat absorbed
$III.$ Change in the internal energy in cycle $= 0$
Which of these are correct
A
$I$ only
B
$II$ only
C
$II$ and $III$
D
$I, II$ and $III$
Solution
The area under the $P-V$ curve gives the work done by the gas.
since initial and final conditions are the same, hence internal energy has not changed which is
a function of $T$ that is temperature. $\Delta U=0$
$Q=W+\Delta U=W$
Hence, the area also shows heat absorbed as it is equal to work done by hte gas.
Answer- $(I I, I I I)$
Standard 11
Physics
