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11.Thermodynamics
medium
Two moles of helium gas are taken over the cycle $ABCDA$, as shown in the $P-T$ diagram. Assuming the gas to be ideal the work done on the gas in taking it from $A $ to $B$ is ...... $R$
A
$300$
B
$400 $
C
$600$
D
$200$
(AIEEE-2009)
Solution
$A$ to $B$ is an isobaric process. The work done
$W = nR\left( {{T_2} – {T_1}} \right) = 2R\left( {500 – 300} \right) = 400R$
Standard 11
Physics
