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3-2.Motion in Plane
easy
Certain neutron stars are believed to be rotating at about $1\,rev/\sec $. If such a star has a radius of $ 20\, km$, the acceleration of an object on the equator of the star will be
A$20 \times {10^8}m/{\sec ^2}$
B$8 \times {10^5}m/{\sec ^2}$
C$120 \times {10^5}m/{\sec ^2}$
D$4 \times {10^8}m/{\sec ^2}$
Solution
(b)$a = {\omega ^2}r = 4{\pi ^2}{n^2}r = 4{\pi ^2} \times {1^2} \times 20 \times {10^3}$
$ a=8 \times {10^5}\;m/{\sec ^2}$
$ a=8 \times {10^5}\;m/{\sec ^2}$
Standard 11
Physics
