Certain neutron stars are believed to be rotating at about $1\,rev/\sec $. If such a star has a radius of $ 20\, km$, the acceleration of an object on the equator of the star will be
$20 \times {10^8}m/{\sec ^2}$
$8 \times {10^5}m/{\sec ^2}$
$120 \times {10^5}m/{\sec ^2}$
$4 \times {10^8}m/{\sec ^2}$
A particle is moving on a circular path of radius $r$ with uniform speed $v$. The magnitude of change in velocity when the particle moves from $P$ to $Q$ is $(\angle POQ = 40^o)$
What happens to the centripetal acceleration of a revolving body if you double the orbital speed $v$ and half the angular velocity $\omega $
A proton of mass $ 1.6 \times 10^{-27} kg$ goes round in a circular orbit of radius $0.10\, m$ under a centripetal force of $4 \times 10^{-13}\, N$. then the frequency of revolution of the proton is about
A string of length $L$ is fixed at one end and carries a mass $M$ at the other end. The string makes $2/\pi$ revolutions per second around the vertical axis through the fixed end as shown in the figure, then tension in the string is
A particle is moving on a circular path with constant speed, then its acceleration will be