Certain neutron stars are believed to be rotating at about $1\,rev/\sec $. If such a star has a radius of $ 20\, km$, the acceleration of an object on the equator of the star will be
$20 \times {10^8}m/{\sec ^2}$
$8 \times {10^5}m/{\sec ^2}$
$120 \times {10^5}m/{\sec ^2}$
$4 \times {10^8}m/{\sec ^2}$
A particle moving with uniform speed in a circular path maintains:
A particle moves in a circle of radius $25\, cm$ at two revolutions per second. The acceleration of the particle in $meter/second^2$ is
Roads are banked on curves so that
A particle $P$ is sliding down a frictionless hemispherical bowl. It passes the point $A$ at $t = 0$. At this instant of time, the horizontal component of its velocity is $v$. A bead $Q$ of the same mass as $P$ is ejected from $A$ at $t = 0$ along the horizontal string $AB$ (see figure) with the speed $v$. Friction between the bead and the string may be neglected. Let ${t_P}$ and ${t_Q}$ be the respective time taken by $P$ and $Q$ to reach the point $B$. Then
An object moves at a constant speed along a circular path in horizontal $XY$ plane with centre at origin. When the object is at $x = -2\,m$ , its velocity is $-(4\,m/ s)\hat j$ . What is object's acceleration when it is at $y = 2\,m$ ?