Charge of 2Q and -Q are placed on two plates of a parallel plate capacitor if capacitance of capacit

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1. Electric Charges and Fields

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Charge of $2Q$ and $-Q$ are placed on two plates of a parallel plate capacitor if capacitance of capacitor is $C$ find potential difference between the plates

A

$V = \frac{Q}{C}$

B

$V = \frac{3Q}{2C}$

C

$V = \frac{2Q}{3C}$

D

None of these

Solution

$\therefore \frac{3}{2} \mathrm{Q}=\mathrm{CV} \Rightarrow \mathrm{V}=\frac{3 \mathrm{Q}}{2 \mathrm{C}}$

Standard 12

Physics

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(AIIMS-2017)