If electric potential of inner shell is 10,V and that of outer shell is 5,V , then potential at cent

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1. Electric Charges and Fields

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If the electric potential of the inner shell is $10\,V$ and that of the outer shell is $5\,V$ , then the potential at the centre will be.....$V$

A

$10$

B

$5$

C

$15$

D

$0$

Solution

$K\left(\frac{q_{1}}{b}+\frac{q_{2}}{a}\right)=10 v K\left(\frac{q_{1}}{b}+\frac{q_{2}}{a}\right)=5 v K\left(\frac{q_{1}+q_{2}}{b}\right)=?$ clearly

$V_{c}=10 V$

Standard 12

Physics

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