Concentration $C{N^ - }$ in $0.1\,M\,HCN$ is $[{K_a} = 4 \times {10^{ - 10}}]$
Concentration $C{N^ - }$ in $0.1\,M\,HCN$ is $[{K_a} = 4 \times {10^{ - 10}}]$
- A
$2.5 \times {10^{ - 6}}M$
- B
$4.5 \times {10^{ - 6}}M$
- C
$6.3 \times {10^{ - 6}}M$
- D
$9.2 \times {10^{ - 6}}M$
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