Concentration C{N^ - } in 0.1,M,HCN is [{Kₐ} = 4 × {10^{ - 10}}]

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6-2.Equilibrium-II (Ionic Equilibrium)

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Concentration $C{N^ - }$ in $0.1\,M\,HCN$ is $[{K_a} = 4 \times {10^{ - 10}}]$

A

$2.5 \times {10^{ - 6}}M$

B

$4.5 \times {10^{ - 6}}M$

C

$6.3 \times {10^{ - 6}}M$

D

$9.2 \times {10^{ - 6}}M$

Solution

Concentration of $CN ^{-1} \sqrt{ K _{ a } \cdot C }$

$=\sqrt{4 \times 10^{-10} \times 0.1}$

$=6.3 \times 10^{-6} \,M$

Standard 11

Chemistry

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