Consider a branch of the hyperbola $x^2-2 y^2-2 \sqrt{2} x-4 \sqrt{2} y-6=0$ with vertex at the point $A$. Let $B$ be one of the end points of its latus rectum. If $\mathrm{C}$ is the focus of the hyperbola nearest to the point $\mathrm{A}$, then the area of the triangle $\mathrm{ABC}$ is

  • [IIT 2008]
  • A

    $1-\sqrt{\frac{2}{3}}$

  • B

    $\sqrt{\frac{3}{2}}-1$

  • C

    $1+\sqrt{\frac{2}{3}}$

  • D

    $\sqrt{\frac{3}{2}}+1$

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