Gujarati
10-2. Parabola, Ellipse, Hyperbola
easy

The eccentricity of the hyperbola $\frac{{\sqrt {1999} }}{3}({x^2} - {y^2}) = 1$ is

A

$\sqrt 3 $

B

$\sqrt 2 $

C

$2$

D

$2\sqrt 2 $

Solution

(b) Here $a = b,$ so it is a rectangular hyperbola.

Hence, eccentricity $e = \sqrt 2 $.

Standard 11
Mathematics

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