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10-2. Parabola, Ellipse, Hyperbola
easy
The eccentricity of the hyperbola $\frac{{\sqrt {1999} }}{3}({x^2} - {y^2}) = 1$ is
A
$\sqrt 3 $
B
$\sqrt 2 $
C
$2$
D
$2\sqrt 2 $
Solution
(b) Here $a = b,$ so it is a rectangular hyperbola.
Hence, eccentricity $e = \sqrt 2 $.
Standard 11
Mathematics