Consider a car moving along a straight horizontal road with a speed of 72, km/h . If coefficient of

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4-2.Friction

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Consider a car moving along a straight horizontal road with a speed of $72\, km/h$. If the coefficient of kinetic friction between the tyres and the road is $0.5,$ the shortest distance in which the car can be stopped is ........ $m$ .$[g = 10\,m{s^{ - 2}}]$

A

$30$

B

$40$

C

$72$

D

$20$

(AIPMT-1992)

Solution

(b)$s = \frac{{{u^2}}}{{2\mu \;g}} = \frac{{{{(20)}^2}}}{{2 \times 0.5 \times 10}} = 40\;m$

Standard 11

Physics

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