Consider a compound slab consisting of two different materials having equal thickness and thermal conductivities $  K$ and $2K$ respectively. The equivalent thermal conductivity of the slab is

  • [AIPMT 2003]
  • A

    $\sqrt {2K} $

  • B

    $3K$

  • C

    $\frac{4}{3}K$

  • D

    $\frac{2}{3}K$

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  • [JEE MAIN 2019]

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  • [IIT 2001]

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  • [NEET 2019]