- Home
- Standard 11
- Physics
10-2.Transmission of Heat
medium
Consider a compound slab consisting of two different materials having equal thickness and thermal conductivities $ K$ and $2K$ respectively. The equivalent thermal conductivity of the slab is
A
$\sqrt {2K} $
B
$3K$
C
$\frac{4}{3}K$
D
$\frac{2}{3}K$
(AIPMT-2003)
Solution
(c) $K = \frac{{2{K_1}{K_2}}}{{{K_1} + {K_2}}} = \frac{{2.K.2K}}{{K + 2K}} = \frac{4}{3}K$
Standard 11
Physics
Similar Questions
medium