Three rods of Copper, Brass and Steel are wel | vedclass

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Question

Rate of heat flow is given by,

$Q = \frac{{KA\left( {{	heta _1} - {	heta _2}} ight)}}{l}$

Where, $K=coefficient\,of\,thermal\,conductivity$

Vedclass · Accepted Answer

$4.8$

Vedclass · Answer

Rate of heat flow is given by,

$Q = \frac{{KA\left( {{	heta _1} - {	heta _2}} ight)}}{l}$

Where, $K=coefficient\,of\,thermal\,conductivity$

$l=length\,of\,rod\,and\,A=Area\,of\,cross-section\,of\,rod$

If the junction temperature is $T$, then

${Q_{Copper}} = {Q_{Brass}} + {Q_{Steel}}$

$\frac{{0.92 	imes 4\left( {100 - T} ight)}}{{46}} = \frac{{0.26 	imes 4 	imes \left( {T - 0} ight)}}{{13}} + $

$\frac{{0.12 	imes4	imes \left( {T - 0} ight)}}{{12}}$

$ \Rightarrow 200 - 2T = 2T + T$

$ \Rightarrow T = {40^ \circ }C$

$	herefore \,\,{Q_{Copper}} = \frac{{0.92 	imes 4 	imes 60}}{{46}} = 4.8\,cal/s$

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