2. Electric Potential and Capacitance
medium

Consider a sphere of radius $R$ having charge $q$ uniformly distributed inside it. At what minimum distance from its surface the electric potential is half of the electric potential at its centre?

A

$R$

B

$\frac{R}{2}$

C

$\frac{4 R}{3}$

D

$\frac{R}{3}$

Solution

(d)

$V_c=\frac{3 k Q}{2 R}$

$V_s=\frac{k Q}{R+x}=\frac{3 k Q}{4 R}$

$4 R=3 R+3 x$

$3 x=R$

$x=\frac{R}{3}$

Standard 12
Physics

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