Consider an atom with atomic number $Z$ as consisting of a positive point charge at the centre and surrounded by a distribution of negative electricity uniformly distributed within a sphere of radius $R$. The electric field at a point inside the atom at a distance $r$ from the centre is
$\frac{ Ze }{4 \pi \varepsilon_0}\left[\frac{1}{r^2}-\frac{r}{R^3}\right]$
$\frac{Z e}{4 \pi \varepsilon_0}\left[\frac{1}{r^2}+\frac{1}{R^3}\right]$
$\frac{2 Z e}{4 \pi \varepsilon_0 r^2}$
$0$
Charges $Q, 2Q$ and $4Q$ are uniformly distributed in three dielectric solid spheres $1,2$ and $3$ of radii $R/2, R$ and $2 R$ respectively, as shown in figure. If magnitudes of the electric fields at point $P$ at a distance $R$ from the centre of spheres $1,2$ and $3$ are $E_1 E_2$ and $E_3$ respectively, then
A conducting sphere of radius $R = 20$ $cm$ is given a charge $Q = 16\,\mu C$. What is $\overrightarrow E $ at centre
According to Gauss’ Theorem, electric field of an infinitely long straight wire is proportional to
The dimensions of an atom are of the order of an Angstrom. Thus there must be large electric fields between the protons and electrons. Why, then is the electrostatic field inside a conductor zero ?
Mention applications of Gauss’s law.