Hydrolysis of BCl ₃ gives X , which on treatment with sodium carbonate produces Y . X and Y , resp

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p-Block Elements - I

hard

Hydrolysis of $BCl _3$ gives $X$, which on treatment with sodium carbonate produces $Y$. $X$ and $Y$, respectively, are

A$H _3 BO _3$ and $NaBO _2$

B$H _3 BO _3$ and $Na _2 B _4 O _7$

C$B _2 O _3$ and $NaBO _2$

D$B _2 O _3$ and $Na _2 B _4 O _7$

(KVPY-2013)

Solution

(b)
Hydrolysis of $BCl _3$ gives boric acid $(X)$, which on treatment with sodium carbonate produces sodium metaborate $(Y)$, carbon dioxide and water.
$BCl _3+3 H _2 O \longrightarrow H _3 \underset{X}{ BO _3}+3 HCl$
$4 H _3 BO _3+ Na _2 CO _3 \longrightarrow \underset{Y}{ Na _2 B _4 O _7}+ CO _2+6 H _2 O$

Standard 11

Chemistry

Which one of the following is the correct statement ?

medium

(AIEEE-2008)

Hoop's process is used for the purification of the metal

easy

The compound($s$) which react($s$) with $NH _3$ to give boron nitride ($BN$) is(are)

$(A)$ $B$ $(B)$ $B _2 H _6$ $(C)$ $B _2 O _3$ $(D)$ $HBF _4$

medium

(IIT-2022)

The type of hybridisation of boron in diborane is

easy

$N{a_2}{B_4}{O_7}.10{H_2}O\xrightarrow{{Heat}}X + NaB{O_2} + {H_2}O,X + C{r_2}{O_3}\xrightarrow{{Heat}}\mathop Y\limits_{\left( {Green\,coloured} \right)} $ $X$ and $Y$ are

normal