For a weak acid $HA,$ Ostwald's dilution law is represented by the equation
${K_a} = \frac{{\alpha c}}{{1 - {\alpha ^2}}}$
${K_a} = \frac{{{\alpha ^2}c}}{{1 - \alpha }}$
$\alpha = \frac{{{K_a}c}}{{1 - c}}$
${K_a} = \frac{{{\alpha ^2}c}}{{1 - {\alpha ^2}}}$
The hydrogen ion concentration of $0.1\,N$ solution of $C{H_3}COOH,$ which is $30\%$ dissociated, is
Ionisation constant of $CH_3COOH$ is $1.7 \times 10^{-5}$ and concentration of $H^+$ ions is $3.4 \times 10^{-4}$. Then find out initial concentration of $CH_3COOH$ Molecules
For a weak acid $HA$ with dissociation constant ${10^{ - 9}},\,\,pOH$ of its $0.1 \,M$ solution is
If degree of ionisation is $0.01$ of decimolar solution of weak acid $HA$ then $pKa$ of acid is
Given the two concentration of $HCN (K_a = 10^{-9})$ are $0.1\,M$ and $0.001\,M$ respectively. What will be the ratio of degree of dissociation ?