Gujarati
Hindi
14.Waves and Sound
normal

Dependence of disturbances due to two waves on time is shown in the figure. The ratio of their intensities $I_1 / I_2$ will be

A

$1 : 1$

B

$1 : 2$

C

$4 : 1$

D

$16 : 1$

Solution

$I=\frac{2 \pi^{2} \rho A^{2} v}{T^{2}} \Rightarrow I \propto\left(\frac{A}{T}\right)^{2}$

$\Rightarrow \frac{I_{1}}{I_{2}}=\left(\frac{A_{1}}{A_{2}} \frac{T_{2}}{T_{1}}\right)^{2}=\left(\frac{1}{2} \times \frac{2}{1}\right)^{2}=1: 1$

Standard 11
Physics

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