Describe the shapes of $BF $$_{3}$ and $BH _{4}^{-}$. Assign the hybridisation of boron in these species.
As a result of its small size and high electronegativity, boron tends to form monomeric covalent halides. These halides have a planar triangular geometry. This triangular shape is formed by the overlap of three $s p^{2}$ hybridised orbitals of boron with the $s p$ orbitals of three halogen atoms. Boron is $s p^{2}$ hybridised in $BF _{3}$. (figure)
$(ii)$ $B H _{4}^{-}$
Boron-hydride ion $(BH_4^-)$ is formed by the $s p^{3}$ hybridisation of boron orbitals. Therefore, it is tetrahedral in structure.(figure)
The liquid field metal expanding on solidification is
Hydrated $AlCl_3$ is used as :
Colour of the bead in borax bead test is mainly due to the formation of
The dissolution of $Al(OH)_3$ by a solution of $NaOH$ results in the formation of
Below are two statements, one labeled as Assertion $(A)$ and the other as Reason $(R):$
Assertion $(A)$: Among group $13$ elements, boron's melting point is unusually high $(2453 \mathrm{~K})$.
Reason $(R):$ Solid boron has a strong crystalline lattice.
In the context of the above statements, choose the correct answer from the following options: