Deutron and α - particle are put 1,mathop Alimits^o apart in air. Magnitude of intensity of electri

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1. Electric Charges and Fields

easy

Deutron and $\alpha - $ particle are put $1\,\mathop A\limits^o $ apart in air. Magnitude of intensity of electric field due to deutron at $\alpha - $ particle is

A

Zero

B

$2.88 \times {10^{11}}\,newton/coulomb$

C

$1.44 \times {10^{11}}\,newton/coulomb$

D

$5.76 \times {10^{11}}\,newton/coulomb$

Solution

(c) Due to deutron, intensity of electric field at $1\, \mathop A\limits^o $ distance,
$E = \frac{1}{{4\pi {\varepsilon _0}}}.\frac{e}{{{r^2}}}$$ = \frac{{9 \times {{10}^9} \times 1.6 \times {{10}^{ – 19}}}}{{{{10}^{ – 20}}}} = 1.44 \times {10^{11}}\,N/C.$

Standard 12

Physics

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