A body of mass $M$ and charge $q$ is connected to a spring of spring constant $k$. It is oscillating along $x-$ direction about its equilibrium position, taken to be at $x = 0$, with an amplitude $A$. An electric field $E$ is applied along the $x-$ direction. Which of the following statements is correct?
The total energy of the system is $\frac{1}{2}m{\omega ^2}{A^2} + \frac{1}{2}\frac{{{q^2}{E^2}}}{k}$
The new equilibrium position is at a distance: $\frac{{2qE}}{k}$ from $x = 0$
The new equilibrium position is at a distance: $\frac{{qE}}{{2k}}$ from $x = 0$
The total energy of the system is $\frac{1}{2}m{\omega ^2}{A^2} - \frac{1}{2}\frac{{{q^2}{E^2}}}{k}$
Two uniform spherical charge regions $S_1$ and $S_2$ having positive and negative charges overlap each other as shown in the figure. Point $O_1$ and $O_2$ are their centres and points $A, B, C$ and $D$ are on the line joining centres $O_1$ and $O_2$. Electric field from $C$ to $D$
For a uniformly charged ring of radius $R$, the electric field on its axis has the largest magnitude at a distance $h$ from its centre. Then value of $h$ is
Two charged particles, each with a charge of $+q$, are located along the $x$ -axis at $x = 2$ and $x = 4$, as shown below. Which of the following shows the graph of the magnitude of the electric field along the $x$ -axis from the origin to $x = 6$?
A charge $Q$ is distributed over a line of length $L.$ Another point charge $q$ is placed at a distance $r$ from the centre of the line distribution. Then the force expericed by $q$ is
In the given figure electric field at center $O$ due to section $AB$ of uniformly charged ring is $\overrightarrow E$. What will be electric field at $O$ due to section $ACB$ ?