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p-Block Elements - I
hard
Diborane $(B_2H_6)$ reacts independently with $O_2$ and $H_2O$ to produce, respectively
A
$H_3BO_3$ and $B_2O_3$
B
$B_2O_3$ and $H_3BO_3$
C
$HBO_2$ and $H_3BO_3$
D
$B_2O_3$ and $[BH_4]^-$
(JEE MAIN-2019)
Solution
$B_2H_6 + 3H_2O \longrightarrow 2H_3BO_3 + 3H_2$
$B_2H_6 + 3O_2 \longrightarrow B_2O_3 + 3H_2O$
Standard 11
Chemistry
