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1.Units, Dimensions and Measurement
easy
Dimensions of stress are
A$\left[ M L ^{-1} T ^{-2}\right]$
B$\left[ M L T ^{-2}\right]$
C$\left[ M L ^{2} T ^{-2}\right]$
D$\left[ M L ^{0} T ^{-2}\right]$
(NEET-2020)
Solution
stress $=\frac{\text { Force }}{\text { Area }}$
$=\frac{M^{1} L^{1} T^{-2}}{L^{2}}$
stress $= M ^{1} L ^{-1} T ^{-2}$
$=\frac{M^{1} L^{1} T^{-2}}{L^{2}}$
stress $= M ^{1} L ^{-1} T ^{-2}$
Standard 11
Physics
Similar Questions
Match List $I$ with List $II$ :
List $I$ (Physical Quantity) | List $II$ (Dimensional Formula) |
$(A)$ Pressure gradient | $(I)$ $\left[ M ^0 L ^2 T ^{-2}\right]$ |
$(B)$ Energy density | $(II)$ $\left[ M ^1 L ^{-1} T ^{-2}\right]$ |
$(C)$ Electric Field | $(III)$ $\left[ M ^1 L ^{-2} T ^{-2}\right]$ |
$(D)$ Latent heat | $(IV)$ $\left[ M ^1 L ^1 T ^{-3} A ^{-1}\right]$ |
Match List $I$ with List $II$
LIST$-I$ | LIST$-II$ |
$(A)$ Torque | $(I)$ $ML ^{-2} T ^{-2}$ |
$(B)$ Stress | $(II)$ $ML ^2 T ^{-2}$ |
$(C)$ Pressure of gradient | $(III)$ $ML ^{-1} T ^{-1}$ |
$(D)$ Coefficient of viscosity | $(IV)$ $ML ^{-1} T ^{-2}$ |