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1.Units, Dimensions and Measurement
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An athletic coach told his team that muscle times speed equals power. What dimensions does he view for muscle
A$ML{T^{ - 2}}$
B$M{L^2}{T^{ - 2}}$
C$ML{T^2}$
D$L$
Solution
(a) According to problem muscle $×$ speed = power
muscle = $\frac{{{\rm{power }}}}{{{\rm{speed}}}} = \frac{{M{L^2}{T^{ – 3}}}}{{L{T^{ – 1}}}}$= $ML{T^{ – 2}}$
muscle = $\frac{{{\rm{power }}}}{{{\rm{speed}}}} = \frac{{M{L^2}{T^{ – 3}}}}{{L{T^{ – 1}}}}$= $ML{T^{ – 2}}$
Standard 11
Physics
Similar Questions
Match List $I$ with List $II$ :
| List $I$ (Physical Quantity) | List $II$ (Dimensional Formula) |
| $(A)$ Pressure gradient | $(I)$ $\left[ M ^0 L ^2 T ^{-2}\right]$ |
| $(B)$ Energy density | $(II)$ $\left[ M ^1 L ^{-1} T ^{-2}\right]$ |
| $(C)$ Electric Field | $(III)$ $\left[ M ^1 L ^{-2} T ^{-2}\right]$ |
| $(D)$ Latent heat | $(IV)$ $\left[ M ^1 L ^1 T ^{-3} A ^{-1}\right]$ |
