Match List I with List II :

List | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

Pressure gradient$=\frac{ dp }{ dx }=\frac{\left[ ML ^{-1} T ^{-2}ight]}{[ L ]}$
$=\left[ M ^1 L ^{-2} T ^{-2}ight]$
Energy density $=\frac{	ex

Vedclass · Accepted Answer

$(A)-(III), (B)-(II), (C)-(IV), (D)-(I)$

Vedclass · Answer

Pressure gradient$=\frac{ dp }{ dx }=\frac{\left[ ML ^{-1} T ^{-2}ight]}{[ L ]}$
$=\left[ M ^1 L ^{-2} T ^{-2}ight]$
Energy density $=\frac{	ext { energy }}{	ext { volume }}=\frac{\left[ ML ^2 T ^{-2}ight]}{\left[ L ^3ight]}$
$=\left[ M ^1 L ^{-1} T ^{-2}ight]$
$	ext { Electric field }=\frac{	ext { Force }}{	ext { ch arge }}=\frac{\left\lfloor MLT ^{-2}ightfloor}{[ A . T ]}$
$=\left[ M ^1 L ^1 T ^{-3} A ^{-1}ight]$
$	ext { Latent heat }=\frac{	ext { heat }}{	ext { mass }}=\frac{\left[ ML ^2 T ^{-2}ight]}{[ M ]}$
$=\left[ M ^0 L ^2 T ^{-2}ight]$

List $I$ (Physical Quantity)	List $II$ (Dimensional Formula)
$(A)$ Pressure gradient	$(I)$ $\left[ M ^0 L ^2 T ^{-2}\right]$
$(B)$ Energy density	$(II)$ $\left[ M ^1 L ^{-1} T ^{-2}\right]$
$(C)$ Electric Field	$(III)$ $\left[ M ^1 L ^{-2} T ^{-2}\right]$
$(D)$ Latent heat	$(IV)$ $\left[ M ^1 L ^1 T ^{-3} A ^{-1}\right]$

Similar Questions

Amount of solar energy received on the earth's surface per unit area per unit time is defined a solar constant. Dimension of solar constant is

The dimension of magnetic field in $M, L, T$ and $C$ (coulomb) is given as

The physical quantity which has the dimensional formula ${M^1}{T^{ - 3}}$ is

Which one of the following does not have the same dimensions

Inductance $L$ can be dimensionally represented as