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6-2.Equilibrium-II (Ionic Equilibrium)
hard
Dimethyl amine ${\left( {C{H_3}} \right)_2}NH$ is weak base and its ionization constant $ 5.4 \times {10^{ - 5}}$. Calculate $\left[ {O{H^ - }} \right],\left[ {{H_3}O} \right]$, $pOH$ and $pH$ of its $0.2$ $M$ solution at equilibrium.
Option A
Option B
Option C
Option D
Solution
$\left[\mathrm{OH}^{-}\right]=1.04 \times 10^{-3} \mathrm{M},\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=9.6 \times 10^{-12} \mathrm{M}, \mathrm{pOH}=2.98, \mathrm{pH}=11.02$
Standard 11
Chemistry
Similar Questions
What is the $pH$ of $0.001 \,M$ aniline solution? The ionization constant of aniline can be taken from Table . Calculate the degree of ionization of aniline in the solution. Also calculate the ionization constant of the conjugate acid of aniline.
Base | $K _{ b }$ |
Dimethylamine, $\left( CH _{3}\right)_{2} NH$ | $5.4 \times 10^{-4}$ |
Triethylamine, $\left( C _{2} H _{5}\right)_{3} N$ | $6.45 \times 10^{-5}$ |
Ammonia, $NH _{3}$ or $NH _{4} OH$ | $1.77 \times 10^{-5}$ |
Quinine, ( $A$ plant product) | $1.10 \times 10^{-6}$ |
Pyridine, $C _{5} H _{5} N$ | $1.77 \times 10^{-9}$ |
Aniline, $C _{6} H _{5} NH _{2}$ | $4.27 \times 10^{-10}$ |
Urea, $CO \left( NH _{2}\right)_{2}$ | $1.3 \times 10^{-14}$ |
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