Assuming that degree of hydrolysis is small, pH of 0.1, M solution of sodium acetate (Kₐ, = 1.0×1

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6-2.Equilibrium-II (Ionic Equilibrium)

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Assuming that the degree of hydrolysis is small, the $pH$ of $0.1\, M$ solution of sodium acetate $(K_a\, = 1.0\times10^{- 5})$ will be

A

$5$

B

$6$

C

$8$

D

$9$

(JEE MAIN-2014)

Solution

sodium acetate is a salt of strong base and weak acid.

$\,pH = 7 + \frac{1}{2}p{K_a} + \frac{1}{2}\,\log \,c$ where

$p{K_a} = – \log \,{K_a} = – \log \,{10^{ – 5}} = 5$

$\log \,c = \log \,{10^{ – 1}} = – 1$

$pH = 7 + \frac{5}{2} – \frac{1}{2} = 9.0$

Standard 11

Chemistry

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