- Home
- Standard 9
- Mathematics
4. Linear Equations in Two Variables
medium
रैखिक समीकरण $2 x+3 y=12$ का आलेख खींचिए। इस समीकरण का आलेख $x-$ अक्ष और $y-$ अक्ष को किन बिंदुओं पर काटता है ?
Option A
Option B
Option C
Option D
Solution
The given equation is $2 x+3 y=12 .$ To draw the graph of this equation, we need at least two points lying on the graph.
From the equation, we have $y=\frac{12-2 x}{3}$
For $x=0, y=4,$ therefore, $(0,4)$ lies on the graph.
For $y=0, x=6,$ therefore, $(6,0)$ lies on the graph.
Now plot the points $A (0,4)$ and $B (6,0)$ and join them (see $Fig.$), to get the line $AB$.
Line $AB$ is the required graph. You can see that the graph (line $AB$) cuts the $x$ -axis at the point $(6,0)$ and the $y$ -axis at the point $(0,4)$
Standard 9
Mathematics
