During an adiabatic process, the pressure of a gas is found to be proportional to the cube of its temperature. The ratio of $\frac{{{C_P}}}{{{C_V}}}$ for the gas is
$2$
$1.67$
$1.5$
$1.33$
A gas for which $\gamma = 1.5$ is suddenly compressed to $\frac{1}{4}$ th of the initial volume. Then the ratio of the final to the initial pressure is
One mole of an ideal gas with $\gamma = 1.4$, is adiabatically compressed so that its temperature rises from $27°C$ to $35°C$. The change in the internal energy of the gas is ....... $J$ $(R = 8.3\,J/mol.K)$
A tyre filled with air $({27^o}C,$ and $2$ atm) bursts, then what is temperature of air ....... $^oC$ $(\gamma = 1.5)$
A van der Waal's gas obeys the equation of state $\left(p+\frac{n^2 a}{V^2}\right)(V-n b)=n R T$. Its internal energy is given by $U=C T-\frac{n^2 a}{V}$. The equation of a quasistatic adiabat for this gas is given by
The pressure and density of a diatomic gas $(\gamma = 7/5)$ change adiabatically from $(P, d)$ to $(P', d')$. If $\frac{{d'}}{d} = 32$, then $\frac{{P'}}{P}$ should be