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11.Thermodynamics
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One mole of an ideal gas with $\gamma = 1.4$, is adiabatically compressed so that its temperature rises from $27°C$ to $35°C$. The change in the internal energy of the gas is ....... $J$ $(R = 8.3\,J/mol.K)$
A
$-166$
B
$166$
C
$-168 $
D
$168$
Solution
(b) Change in internal energy of the gas
$\Delta U = – \,\Delta W\frac{R}{{\gamma – 1}}\left[ {{T_2} – {T_1}} \right]$$ = \frac{{8.3}}{{(1.4 – 1)}}[308 – 300] = 166J$
Standard 11
Physics
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