11.Thermodynamics
medium

One mole of an ideal gas with $\gamma = 1.4$, is adiabatically compressed so that its temperature rises from $27°C$ to $35°C$. The change in the internal energy of the gas is ....... $J$ $(R = 8.3\,J/mol.K)$

A

$-166$

B

$166$

C

$-168 $

D

$168$

Solution

(b) Change in internal energy of the gas
$\Delta U = – \,\Delta W\frac{R}{{\gamma – 1}}\left[ {{T_2} – {T_1}} \right]$$ = \frac{{8.3}}{{(1.4 – 1)}}[308 – 300] = 166J$

Standard 11
Physics

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