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10-2. Parabola, Ellipse, Hyperbola
medium
Eccentricity of conjugate hyperbola of $16x^2 - 9y^2 - 32x - 36y - 164 = 0$ will be-
A
$\frac{5}{3}$
B
$\frac{5}{4}$
C
$\frac{12}{5}$
D
$\frac{13}{12}$
Solution
Solution is Lorem ipsum dolor sit amet, consectetur adipiscing elit. Ut elit tellus, luctus nec ullamcorper mattis, pulvinar dapibus leo.
Standard 11
Mathematics