Eccentricity of conjugate hyperbola of $16x^2 - 9y^2 - 32x - 36y - 164 = 0$ will be-
Eccentricity of conjugate hyperbola of $16x^2 - 9y^2 - 32x - 36y - 164 = 0$ will be-
- A
$\frac{5}{3}$
- B
$\frac{5}{4}$
- C
$\frac{12}{5}$
- D
$\frac{13}{12}$
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- [JEE MAIN 2022]
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